What is the average of the integers from 9 to 192? Here we will show you how to calculate the average of the integers from 9 to 192.
To calculate the average of any set of numbers, you divide the sum of the numbers by the total numbers in the set (Sum/Total).
Therefore, to calculate the average of the integers from 9 to 192, we need to divide the sum of the integers from 9 and 192 by the total number of integers from 9 to 192. Here are step-by-step instructions:
Step 1) Calculate Sum of Numbers
First, we calculate the sum of all the integers (whole numbers) from 9 to 192 by using a formula where a is the low number of 9 and b is the high number of 192:
Sum = ((b - a + 1) ÷ 2) × (a + b)
Sum = ((192 - 9 + 1) ÷ 2) × (9 + 192)
Sum = (184 ÷ 2) × (201)
Sum = 92 × 201
Sum of Numbers = 18492
Step 2) Calculate Total Number
Next, we calculate the total number of integers from 9 to 192. To calculate the total number of integers, we calculate the difference between 9 and 192 and then add 1. Here is the formula and the math. Once again, a is the low number of 9 and b is the high number of 192:
Total = b - a + 1
Total = 192 - 9 + 1
Total Number = 184
Step 3) Calculate the Average
Now we have both pieces needed to calculate the average of the integers from 9 to 192. We calculate the average of the integers by dividing the Sum of Numbers from Step 1 by the Total Number from Step 2. Here is the math and the answer:
Average = Sum of Numbers ÷ Total Number
Average = 18492 ÷ 184
Average = 100.5
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