What is the average of the integers from 8 to 48? Here we will show you how to calculate the average of the integers from 8 to 48.
To calculate the average of any set of numbers, you divide the sum of the numbers by the total numbers in the set (Sum/Total).
Therefore, to calculate the average of the integers from 8 to 48, we need to divide the sum of the integers from 8 and 48 by the total number of integers from 8 to 48. Here are step-by-step instructions:
Step 1) Calculate Sum of Numbers
First, we calculate the sum of all the integers (whole numbers) from 8 to 48 by using a formula where a is the low number of 8 and b is the high number of 48:
Sum = ((b - a + 1) ÷ 2) × (a + b)
Sum = ((48 - 8 + 1) ÷ 2) × (8 + 48)
Sum = (41 ÷ 2) × (56)
Sum = 20.5 × 56
Sum of Numbers = 1148
Step 2) Calculate Total Number
Next, we calculate the total number of integers from 8 to 48. To calculate the total number of integers, we calculate the difference between 8 and 48 and then add 1. Here is the formula and the math. Once again, a is the low number of 8 and b is the high number of 48:
Total = b - a + 1
Total = 48 - 8 + 1
Total Number = 41
Step 3) Calculate the Average
Now we have both pieces needed to calculate the average of the integers from 8 to 48. We calculate the average of the integers by dividing the Sum of Numbers from Step 1 by the Total Number from Step 2. Here is the math and the answer:
Average = Sum of Numbers ÷ Total Number
Average = 1148 ÷ 41
Average = 28
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