
What is the average of the integers from 5 to 98? Here we will show you how to calculate the average of the integers from 5 to 98.
To calculate the average of any set of numbers, you divide the sum of the numbers by the total numbers in the set (Sum/Total).
Therefore, to calculate the average of the integers from 5 to 98, we need to divide the sum of the integers from 5 and 98 by the total number of integers from 5 to 98. Here are step-by-step instructions:
Step 1) Calculate Sum of Numbers
First, we calculate the sum of all the integers (whole numbers) from 5 to 98 by using a formula where a is the low number of 5 and b is the high number of 98:
Sum = ((b - a + 1) ÷ 2) × (a + b)
Sum = ((98 - 5 + 1) ÷ 2) × (5 + 98)
Sum = (94 ÷ 2) × (103)
Sum = 47 × 103
Sum of Numbers = 4841
Step 2) Calculate Total Number
Next, we calculate the total number of integers from 5 to 98. To calculate the total number of integers, we calculate the difference between 5 and 98 and then add 1. Here is the formula and the math. Once again, a is the low number of 5 and b is the high number of 98:
Total = b - a + 1
Total = 98 - 5 + 1
Total Number = 94
Step 3) Calculate the Average
Now we have both pieces needed to calculate the average of the integers from 5 to 98. We calculate the average of the integers by dividing the Sum of Numbers from Step 1 by the Total Number from Step 2. Here is the math and the answer:
Average = Sum of Numbers ÷ Total Number
Average = 4841 ÷ 94
Average = 51.5
Average of Integers in a Sequence Calculator
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